The context for the problems was ...
Roimata's whanau is hosting a hui on their marae. They are getting te whare kai ready. There will be 14 Kaumatua and speakers at the top table. There is also room for 16 tables that each seat 9 people and 2 tables that each seat 8 people.
The problem is :
Question 1 :
How many people can be seated in the room ?
Answer/Strategy:
Answer: 174 People
16 Tables - 9 Each 2 Tables - 8 Each
16x9=144
(9x10=90)+(9x6=54) =144
8x2=16
144+16= 160 (Not including the Kaumatua)
14 Kaumatua
160+14= 174 PeopleSo that was the problem from yesterday. Stay in tune tomorrow for question 2.
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